2x/6=(x^2+7x)/15

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Solution for 2x/6=(x^2+7x)/15 equation: 



2x/6=(x^2+7x)/15

We move all terms to the left:

2x/6-((x^2+7x)/15)=0

We calculate fractions


30x^2/()+(-((x^2+7x)*6)/()=0



We calculate terms in parentheses: +(-((x^2+7x)*6)/(), so:

-((x^2+7x)*6)/(

We multiply all the terms by the denominator


-((x^2+7x)*6)



We calculate terms in parentheses: -((x^2+7x)*6), so:

(x^2+7x)*6

We multiply parentheses

6x^2+42x

Back to the equation:

-(6x^2+42x)



We get rid of parentheses

-6x^2-42x

Back to the equation:

+(-6x^2-42x)



We get rid of parentheses

30x^2/()-6x^2-42x=0

We multiply all the terms by the denominator


30x^2-6x^2*()-42x*()=0

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